If the sum of first n even natural numbers is equal to k times the sum of first n odd natural numbers,then K will be???
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sum of first n even natural numbers = n(n+1)
sum of first n odd natural numbers = n^2
so k = ( n+1 ) ÷ n
sum of first n odd natural numbers = n^2
so k = ( n+1 ) ÷ n
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