Question

if the sum of first n odd natural numbers is 1225 find the value of n​

Answer 1

Answer:

AP=1,3,5,.....

a=1, d=3-1=2, Sn=1225

Sn=n/2[2a+(n-1)d]

1225=n/2[2(1)+(n-1)2]

1225=n/2(2+2n-2)

1225=n/2(2-2+2n)

1225=n/2×2n

1225=2n²/2

1225=n²

n=√1225

n=35

Answer 2

Answer:

n=35

PLEASE MAKE ME BRAINLEAST