If the sum of first n' successive even natural numbers is 72 then formulate the quadratic equation to find 'n'.
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Heyyy
Step-by-step explanation:
Sn = n/2 [2a + (n-1)d]
72 × 2 = n [2a + (n-1)d]
144 = n [2a + dn -d]
144 = 2an + dn^2 -dn
dn^2 - dn + 2an = 144
dn^2 - (d - 2a)n - 144 = 0
Which is the required quadratic equation.
Hope it helped...
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