If the sum of first n' successive even natural numbers is 72 then formulate the quadratic equation to find 'n'.
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Step-by-step explanation:
Even Natural numbers are : 2,4,6,8... and so on till infinity.
So our A.P (Arithmetic Progression) is =2,4,6,8,...
So, a ( first term) = 2, d = 2
Sn=n/2[ 2a + (n-1) × d ]
72= n/2 (2a + dn - d)
72 = n/2 (2×2 + 2n - 2)
72 = n/2 (2 + 2n)
72 = 2n/2 + 2n×n
72 = n + 2n×n
Final Answer:
2n×n + n - 72 = 0
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