If the sum of first 'n' successive even natural numbers is 72,
then formulate the quadratic equation to find 'n'.
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Answer:
2n^2+3n+1)=432/n
Step-by-step explanation:
n(n+1)(2n+1)/6=72
n(n+1)(2n+1)= 432
n(2n^2+3n+1)=432
2n^2+3n+1)=432/n
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