if the sum of first n tems is n^2 then find it's 10th term
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Sum of the first n term of an AP is,
Sn = n²
S1 = 1² = 1
S2 = 2² = 4
S3 = 3² = 9
S4 = 4² = 16
…. and so on
Now, first term T1=S1 = a = 1
Next few terms,
T2 = S2-S1 = 4–1 =3
T3 = S3-S2 = 9–4 =5
T4 = S4-S3 = 16–9 = 7
…. and so on
Common difference d = 5–3 =7–5= 2
nth term of AP is, Tn = a+(n-1)d
For 10 th term, n=10
T10 = 1+(10–1) 2 = 19
Ans: 10th term is 19
Step-by-step explanation:
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