if the sum of first n term of an ap is 3n^2+2n find the AP
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Answer:
Sn=3n^2+2n
TO FIND:nth term
we have to find value of a&d i.e
first term &common difference
put n=1
S1=3(1)^2+2(1)
s1=3+2
s1=5
putn=2
s2=3(2)^2+2(2)
s2=12+4
s2=16
now,
a=t1=s1
a=t1=5
t2=s2-s1
=16-5
t2=11
a=5
d=t2-t1
=11-5
d=6
tn=a+(n-1)d...................(formula)
tn=5+(n-1)6....(substituting value)
tn=5+6n-6
tn=6n-1
As a result
the nth term is 6n-1
Step-by-step explanation:
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Answer:
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