If the sum of first n term of an ap is given by sn=3nsquare+ 2nfind the nth term of the AP
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Step-by-step explanation:
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Answer:
nth term of AP is 6n-1
Step-by-step explanation:
Given Equation is
Sn= 3n^2+2n
Let value of n=1
S1= 3+2=5
Let value of n=2
S2= 3x(2)2+2x2
= 12+4
=16
Here First term S1=a= 5
Difference d= S2-S1= 16-5=11
nth term of AP
Nth term Tn= a+(n-1)d
Tn= 5+(n-1)6
Tn= 5+6n-6
Tn=6n-1
Therefore nth term of AP is 6n-1
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