If the sum of first n terms of an A.P. is (1/2)(3n² + 7n), then find its nth term. Hence write its 20th term.
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62
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The nth term of the A.P is equal to 5 + (n-1)×3.
The 20th term of the A.P is equal to 62.
Given that the sum of n terms of an A.P is equal to (1/2)(3n² + 7n) .
S1 (sum of the 1st term) = (1/2)(10) = 5 = a
S2(sum of 1st and 2nd term) = (1/2)(26) = 13 = a + a + d
=> 2a + d = 13
=> d = 13 - 10
=> d = 3
Common difference of the arithmetic progression is 3 and the first term is 5.
Nth term = 5 + (n-1)×3
The 20th term of the arithmetic progression= 5 + (20-1)×3
= 5 + 57
= 62
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