If the sum of first n terms of an A.P. is 2n2 + 5n, then find its nth term.
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Sum of first n terms of AP, Sn = 2n2 + 5n
Now choose n =1 and put in the above formula,
First term = 2+5 = 7
Now put n=2 to get the sum of first two terms = 2x4 + 5x 2= 8 + 10 = 18
This means
first term + second term = 18
but first term =7 as calculated above
so, second term = 18-7 = 11
So common difference becomes, 11-7 = 4
So the AP becomes, 7, 11, 15, ....
nth term = a + (n - 1)d = 7 + (n-1)4 = 7 + 4n - 4 = 3 + 4n
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