Question

if the sum of first n terms of an A.P is given by Sn=4n2-3n then find the nth term of an A.P

Answer 1

see above that is correct

Answer 2

Sn=4n^2-3n
An=Sn-Sn-1
    =4n^2-3n-[4(n-1)^2-3(n-1)]
    =4n^2-3n-4n^+4+3n-3
    =4-3
    =1