if the sum of first n terms of an AP be 3n^2-n and its common difference is 6 ,the its first term is....?
please solve it step by step....
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we have,
sum of first n terms = 3n^2-n
sum of first term = 3×1^2-1
= 3-1
= 2
now first term = sum of first term
therefore first term = 2
sum of first n terms = 3n^2-n
sum of first term = 3×1^2-1
= 3-1
= 2
now first term = sum of first term
therefore first term = 2
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