If the sum of first n terms of an AP is 3n² + 2n , find the A.P.
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Answer:
here we have to make an AP
it is very easy we just have to replace n by any consecutive group of numbers like=
3[1]²+2[1]=5
3[2]²+2[2]=16
3[3]²+2[3]=33
so the AP is 5,16,33
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