if the sum of first n terms of an ap is 4n^2-n , find it 12th term
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n=12
S12=4(12)^2-12
=4(144)-12
=576-12
=564
S11=4(11)^2-11
=4(121)-11
=484-11
=473
S12-S11= 12th term
564-473=91
the 12th term is 91
am I ri8
S12=4(12)^2-12
=4(144)-12
=576-12
=564
S11=4(11)^2-11
=4(121)-11
=484-11
=473
S12-S11= 12th term
564-473=91
the 12th term is 91
am I ri8
Attachments:
malalalice:
y did we take s11?
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