if the sum of first n terms of an AP is 4n- n² . find its nth term
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Answer:
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Step-by-step explanation:
first
let's take a1 as 1,therefore,
4n-n^2=4(1)-(1)^2
=4-1
=3
then,take,
a2=2
4n-n^2
=4(2)-(2)^2
=8-4
=4
then subtract s2-s1,we get a2=1
by subtracting s1 which is equal to a1 with s1 we get -2 which is common difference
then apply the formula of
an=a+(n-1)d
where an=1
a=3
d=-2
find the value of n by substituting the values and simplification
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