Question

If the sum of first n terms of an AP is 4n2- n,find its 12th term

Answer 1

Answer :

Given that,

$S_n$ = 4n² - n

Then, the 12th term be

$t_{12} = S_{12} - S_{11}$

= {4 (12²) - 12} - {4 (11²) - 11}

= {4 (144) - 12} - {4 (121) - 11}

= 564 - 473

= 91

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Answer 2

Answer:

required answer should be 91

Step-by-step explanation:

given

Sn=4n²-n

for the 12th term

a12=S12-S11

a12=[4(12²)-12] -[4(11²)-11]

= [4(144)-12] - [4(121)-11]

=(576-12) - (484-11)

=564-476

=91

THE 12th TERM IS 91