If the sum of first n terms of an AP is n(n+10),then find the first term and common difference
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first term=1(1+10)=11
sum of 1st and 2nd term=2(2+10)=24
2nd term=24-11=13
common difference=13-11=3
sum of 1st and 2nd term=2(2+10)=24
2nd term=24-11=13
common difference=13-11=3
namanjain611:
chl be glt ans h ye
Answered by
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first term = s1 = a
n(n+10)=1(1+10)=1(11)=11
so similarly s2 = 24 so
now a2= s2-s1
= 24-11= 13 so
d= 13-11=2
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