If the sum of first n terms of two AP's are in the ration 3n+5 is to 5n+7 , thgen find the ratio of their nth terms
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sum of n terms of an AP= n/2{2a+(n-1)d}
hence the said ratio=2a+(n-1)d/2a'+(n-1)d'= 3n+5/5n+7
hence d=3 , d'=5 ,a= 4 , a'=6
nth term= a+(n-1)d
hence required ratio is
4+(n-1)3/ 6+(n-1)5= 3n+1/5n+1
hence the said ratio=2a+(n-1)d/2a'+(n-1)d'= 3n+5/5n+7
hence d=3 , d'=5 ,a= 4 , a'=6
nth term= a+(n-1)d
hence required ratio is
4+(n-1)3/ 6+(n-1)5= 3n+1/5n+1
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