If the sum of first p term of an A.P. is + bp, find its common difference.
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Answer:
The common Difference is 2a .
Step-by-step explanation:
Given :
Sp = ap² + bp……….(1)
On putting n = 1 in eq (1),
S1 = a(1)² + b(1)
S1 = a + b
On putting n = 2in eq (1),
S2 = a(2)² + b(2)
S2 = a × 4 + 2b
S2 = 4a + 2b
a2 = S2 - S1
[nth term of the A.P., an = Sn – S(n – 1)]
a2 = 4a + 2b - (a + b)
a2 = 4a + 2b - a - b
a2 = 4a - a + 2b - b
a2 = 3a + b
Common difference , d = a2 - a1
d = 3a + b – (a + b)
d = 3a + b - a - b
d = 2a
Hence,the common Difference is 2a .
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