If the sum of first ten term of snaps is 100 & sum of the first twenty term of an AP is 400. Find the sum of first twenty five terms
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2a+9d=20
2a+19d=40
d=2
d=2 in eq1
a=1
S25=675
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Answer:
Step-by-step explanation:
Here sum of ten terms is given that 100 . It means that S10=100 here n=10. So 10/2(2a+(10-1)d=100 and now. By solving it we get. 2a+9d=20 ...........(1) and sum of twenty terms is 400 it means that S20=400 and n=20 so 20/2(2a+19d)=400 so. 2a+19d=40 .........(2) and by solving (1)and(2) we get d=2 and by putting the value of d in (1) we get a=1 and now S25=25/2(2a+24d)
and by substituting the value of a and d in it we get S25=625 so sum of twenty five terms is 625
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