Question

If the sum of first ten terms of an A.P.is 4 times the
sum of the first five terms, then find the ratio of the
first term to the common difference.​

Answer 1

Answer:

A

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Sn= (n/2)(2a+(n-1)d)

Given S10 = 4S5

(10/2)(2a+(10-1)d) = 4(5/2)(2a+(5-1)d)

5(2a+9d) = 10(2a+4d)

2a+9d = 2(2a+4d)

2a+9d = 4a+8d

9d – 8d = 4a-2a

d = 2a

a/d = 1/2

So the ratio is 1:2.

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