Question

If the sum of first three natural
numbers from a group of six
consecutive natural numbers is 36,
then the sum of last three natural
numbers will be:
(1) 45
(2) 52
(3) 56
(4) 55​

Answer 1

Answer:

The last three consecutive numbers are :

→ 14, 15, and 16

Their sum is 45.

Step-by-step explanation:

Given that,

• In group of natural consecutive numbers the sum of first three natural consecutive numbers is : 36

Here, the first three consecutive numbers sums to 36. We need to find the last three numbers.

✦ Considering the first three numbers as :

→ x

→ (x + 1)

→ (x + 2)

✦ According to the question :

⇒ x + (x + 1) + (x + 2) = 36

⇒ x + x + 1 + x + 2 = 36

⇒ 3x + 3 = 36 [Subtract both side by 3]

⇒ 3x = 33 [Divide both side by 3]

⇒ x = 11

✦ Hence, the value of x we got is 11

So the first three numbers are :

→ x = 11

→ (x + 1) = 12

→ (x + 2) = 13

• As they are natural consecutive numbers.

✦ The last three number will be :

→ 13 + 1 = 14

→ 13 + 2 = 15

→ 13 + 3 = 16

Their sum is :

→ 14 + 15 + 16

→ 45 ☑

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