If the sum of first three terms of AP is 27 then find first term
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3
Answer:
Sum of first three terms=27
a-d + a + a + d = 27
3a = 27
a=9
Sum of the squares= 29
(a-d) ^2 +(a) ^2 + (a+d)^2=29
a^2 +d^2 -2ad +a^2 +a^2 +d^2 +2ad =29
3a^2 + 2d^2 = 29
3×9×9. + 2d^2=29
243 +2d^2=29
2d^2= -214
d^2=-107
d= √-107
Answered by
0
Step-by-step explanation:
let be the 3 no be x
(x+1)+(×+2)+(×+3)
3×+6=27
3×=27_6
3×=21
×=21/3
×=7 ans
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