if the sum of five consecutive integers is 40, what is the smallest of the five integers
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Answer:
smallest number will be 6
Step-by-step explanation:
Let x be the smallest. Then the next four consecutive integers are x+1, x+2, x+3, and x+4. Their sum is x + x+1 + x+2 + x+3 + x+4 = 5x+10
Now we know this 5x+10 = 40. 5x = 30. x = 6. Therefore x=6 is the smallest integer (and only integer) such that the next 4 numbers added together along with 6 is 40. Therefore smallest number is 6 .
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Answer:
smallest integer is 6...
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