If the sum of five consecutive integers is S, then the largest of those integers in terms of S is
Answers
Answered by
3
Que.If the sum of five consecutive integers is S, then the largest of those integers in terms of S is?
Let the smallest of five consecutive numbers be x, hence other four consecutive numbers are x + 1, x + 2, x + 3 and x + 4
Their sum
x + x + 1 + x + 2 + x + 3 + x + 4 = s
5x + 10 = s
5x = s - 10
x = s - 10/5
The smallest of five consecutive numbers is (s - 10)/5. Hence largest of five consecutive numbers is
x + 4
= (s - 10)/5 + 4
= (s - 10 + 20)/5
= (s + 10)/5
Thus the largest of five consecutive numbers is (s + 10)/5
Answer : Largest of five consecutive number in terms of s is (s + 10/5
Answered by
1
Answer:
Largest of five consecutive number in terms of s is (s + 10/5
Step-by-step explanation:
please subscribe my channel Arnav educational
Similar questions