Math, asked by sabinaji879, 5 hours ago

if the sum of five consecutive numbers is 60 then the first number is ​

Answers

Answered by TwilightShine
5

Answer :-

  • The first number is 10.

To find :-

  • The first number.

Solution :-

Let the first number be "x".

Then :-

  • The next four consecutive numbers will be "x + 1", "x + 2", "x + 3" and "x + 4".

It is given that :-

  • Their sum is 60.

Therefore,

 \leadsto\sf x + x + 1 + x + 2 + x + 3 + x + 4 = 60

Adding all the variables,

 \leadsto\sf5x + 1 + 2 + 3 + 4 = 60

Adding all the constants,

 \leadsto\sf5x + 10 = 60

Transposing 10 from LHS to RHS, changing it's sign,

 \leadsto\sf5x = 60 - 10

Subtracting 10 from 60,

 \leadsto\sf5x = 50

Transposing 5 from LHS to RHS, changing it's sign,

 \leadsto\sf x =  \dfrac{50}{5}

Dividing 50 by 5,

 \leadsto\underline{ \boxed{\sf x = 10}}

 \\

Hence :-

  • The first number is 10, because we had taken it as x.

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And the other numbers are as follows :-

 \bf x + 1 = 10 + 1 = 11.

 \bf x + 2 = 10 + 2 = 12.

 \bf x + 3 = 10 + 3 = 13.

 \bf x + 4 = 10 + 4 = 14.

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