Question

If the sum of five consecutive odd number is 295 then what is the smallest number

Answer 1

Let the common multiple be x

So, let the five consecutive odd numbers be x, x + 2, x + 4, x + 6 and x + 8

Given : Their sum is 295


According to the given condition

x + x + 2 + x + 4 + x + 6 + x + 8 = 295

☛ 5x + 20 = 295

☛ 5x = 295 - 20

☛ 5x = 275

Dividing both the sides by 5, we get :

∴ x = 55


∴ The smallest number ☛ x

☛ $\large{\boxed{\boxed{\textsf{55}}}}$

Answer 2

$\underline{\underline{\bold{Question:}}}$

If the sum of five consecutive odd number is 295 .What is the smallest number ?

$\tt{Solution:}$

$\boxed{\bold{\textsf{The difference between of two consecutive odd no. will be always 2.}}}$

Let the smallest odd no. be x.

So

• 2nd odd no. = (x+2).
• 3rd odd no. = (x+2+2) = (x+4).
• 4th  odd no. = (x+4+2) = (x+6).
• 5th odd no. = (x+6+2) = (x+8).

According to question ,

The sum of five consecutive odd number is 295.

$\implies{\bold{x+(x+2)+(x+4)+(x+6)+(x+8)=295}}\\\\\\\implies{\bold{5x+20=295}}\\\\\\\implies{\bold{5x=295-20}}\\\\\\\implies{\bold{5x=275}}\\\\\\\implies{\bold{x=\dfrac{275}{5}}}\\\\\\\implies{\bold{x=55.}}\\\\\\\boxed{\boxed{\bold{The\:Smallest\:odd\:no.=x=55.}}}$