Math, asked by kshahalam270, 5 hours ago

If the sum of five different counting numbers is 2175,
which of the following can be value of the maximum
even number among those five numbers?​

Answers

Answered by sammansarraf57
1

Answer:

2,175 (two thousand one hundred seventy-five) is an odd four-digits composite number following 2174 and preceding 2176. In scientific notation, it is written as 2.175 × 103. The sum of its digits is 15. It has a total of 4 prime factors and 12 positive divisors. There are 1,120 positive integers (up to 2175) that are relatively prime to 2175.

Answered by yusufkhanstar29
0

Answer:

436

Step-by-step explanation:

Concept= Addition

Given= The sum of five counting numbers.

To find= The maximum even number out of the five numbers.

Explanation=

We have been given the question as if the sum of five different counting numbers is 2175, which of the following can be value of the maximum even number among those five numbers?

So we know that sum of five numbers is 2175.

It is also mentioned as the numbers are the counting numbers.

So the number are natural number and we consider them to be consecutive numbers.

Let the numbers be x, x+1, x+2, x+3 and x+4.

These are the five numbers and their sum is 2175.

So, x + x+1 + x+2 + x+3 + x+4 = 2175

=> 5x + 10 = 2175

=> 5x= 2175-10

=> 5x = 2165

=> x = 2165/5

=> x= 433

So we get the value of x as 433. This is our first number.

So, now the numbers are:

x= 433

x+1 = 434

x+2= 435

x+3 = 436

x+4 = 437

So we get the numbers as 433,434,435,436 and 437.

We need to find the maximum even number. The even numbers are 434 and 436.

Amongst 434 and 436 we see that 436 is the maximum even number.

#SPJ3

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