Question

if the sum of four alternate integer is 1292 then what would be the largest integer​

Answer 1

Answer:

x+x+2+x+4+x+6=1292

4x+12=1292

4x=1292-12

4x=1280

x=1280/4

x=320

x=320

x+2=320+2=322

x+4=320+4=324

x+6=320+6=326

largest integer =326