Question

if the sum of four alternate integers is 1292 then what would be the largest of these integers?​

Answer 1

Let four consecutive even numbers be:

x,x+2,x+4,x+6

According to the question,  

x+x+2+x+4+x+6=92

⟹4x+12=92

x=  

4

80

​

=20

∴ the largest number among them is  x+6 = 20+6 = 26

Answer 2

answer: 326

x + x+2 + x + 4 + x +6 = 1292

4x + 12 =1292

4x=1280

x=320

largest number = x+6

= 320 +6

= 326