Question

If the sum of four alternate integers is 1292,then what would be the largest of these integers?

Answer 1

Answer:

43

Step-by-step explanation:

Let the four consecutive odd positive integers are x,x+2,x+4,x+6

∴x+x+2+x+4+x+6=160

4x+12=160

4x=160−12

4x=148

x=  

4

148

​

Answer 2

Answer:

326

Step-by-step explanation:

let four alternate integers are :--- x, x+2, x+4 & x+6

x + x+2 + x + 4 + x +6 = 1292

4x + 12 =1292

4x=1280

x=320

largest number = x+6

= 320+6

=326