Question

If the sum of four consecutive even number is 476. Find the number

Answer 1

$\huge \mathcal\colorbox{lightblue}{Hello...}$

__________________________

Let the four consecutive even number be

• x
• x+2
• x+4
• x+6

:. sum of all consecutive even numbers = 476

=> x+(x+2)+(x+4)+(x+6) = 476

=> 4x + 12 = 476

=> 4x = 476 -12

=> 4x = 464

=> x = 464 ÷ 4

=> x = 116

Thus, The consecutive even numbers are:

• (x) = 116
• (x+2)=118
• (x+4)=120
• (x+6)=122

__________________________

Thanks...

Answer 2

Answer :-

The numbers are 116, 118, 120 and 122.

Step-by-step explanation:

To Find :-

• The four consecutive even numbers.

★ Solution

Given that,

• The sum of four consecutive even numbers is 476

Assumption

Let us assume the consecutive even numbers as (x), (x + 2), (x + 4) and (x + 6).

∴ (x) + (x + 2) + (x + 4) + (x + 6) = 476

⇒ x + (x + 2) + (x + 4) + (x + 6) = 476

⇒ x + x + 2 + x + 4 + x + 6 = 476

⇒ 4x + 2 + 4 + 6 = 476

⇒ 4x + 12 = 476

⇒ 4x = 476 - 12

⇒ 4x = 464

⇒ x = 464/4

⇒ x = 116

The value of x is 116.

Now, The number are :-

• x = 116
• (x + 2) = (116 + 2) = 118
• (x + 4) = (116 + 4) = 120
• (x + 6) = (116 + 6) = 122

Hence,

The even consecutive numbers are 116, 118, 120 and 122.

⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

V E R I F I C A T I O N :-

• (x) + (x + 2) + (x + 4) + (x + 6) = 476

By simplifying the L.H.S, by putting the value of numbers :-

⇒ (x) + (x + 2) + (x + 4) + (x + 6)

⇒ 116 + 118 + 120 + 122

⇒ 476

∴ L.H.S = R.H.S = 476

Hence, Verified!