if the sum of frist 6 terms of an AP is 36 and that of the frist sixteen terms is 256 . find the sum of frist 10 terms.
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If the sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256
If sum of first 6 terms of an AP is 36 and that of the first 16 terms is 256 , then find the sum of first 10 terms. Solution : Let a d be the first term and common difference, respectively of an AP. Hence, the required sum of first 10 terms is 100.
Step-by-step explanation:
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1
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110
Step-by-step explanation:
S6 = 36
6/2( 2a + 5d) = 36
2a + 5d = 12
2a = 12 - 5d.................................. (1)
Now, S16 = 256
256 = 16/2( 2a +15d )
2a +15d = 32
12 - 5d +15d = 32 (by 1)
d = 2
a = 2
S10 = 10/2 ( 2*2 + 9*2 )
110
ANSWER IS 110
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