Question

if the sum of interior angles of polygon is 3 times the sum of exterior angles then the number of sides of a polygon is----------------

Answer 1

Sum of interior angles = (n-2)180
Sum of exterior angles = 360
(n-2)180=3 (360)
n-2=6
n=8

Answer 2

Answer:

Sum of interior angles = (no. of sides -2) *180

Sum of exterior angles = 360

(n-2) *180 =3*360

no. of sides - 2 = 6

no.of sides = 6+2

                  = 8

Step-by-step explanation: