If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is
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let the HCF be x and LCM be 900+x
x+900+x=1260
2x=1260-900
2x=360
x=360/2
x=180
hence,hcf be 180 and lcm be 900+180=1080
product of two no.=1080×180=194400
x+900+x=1260
2x=1260-900
2x=360
x=360/2
x=180
hence,hcf be 180 and lcm be 900+180=1080
product of two no.=1080×180=194400
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HEY FRIEND HERE IS UR ANSWER ,
Given that the sum of HCF and LCM = 1260.
LCM + HCM = 1260 --------------------- (1)
Given that their LCM is 900 more than the HCF.
Let HCF = x. ------------ (2)
Then the LCM = 900 + x. ------------------- (3)
On solving (1),(2),(3).
1260 = x + (900 + x)
1260 = x + 900 + x
1260 = 2x + 900
1260 - 900 = 2x
360 = 2x
x = 360/2
x = 180.
Now, we got
HCF = 180.
Then, LCM = 900
= 900 + 180
= 1080.
We know that product of two numbers = HCF * LCM
= 180 * 1080
= 194400.
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