Question

If the sum of LCM and HCF of two numbers is 1260 and their LCM is 900 more than their HCF, then the product of two numbers is

Answer 1

hola!
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Given :

H.C.F + L.C.M = 1260 ----(i)

and  L.C.M = H.C.F + 900

On putting the value of L.C.M in eqn. (i) we get

H.C.F + H.C.F + 900 = 1260

⇒ 2 H.C.F = 360

⇒  H.C.F = 180

∴ L.C.M = 900 + 180 = 1080

We know, 

Product of two numbers = H.C.F. × L.C.M.

⇒ Product of two numbers = 180 × 1080

⇒ Product of two numbers = 194400

Hence,
The product of two numbers id 19440

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Hope it helps! :D

Answer 2

Hii friend,

Let the HCF of two numbers be X.

Then the LCM of two numbers = (X+900)

According to question,

(X+900 + X) = 1260

2X = 1260-900

2X = 360

X = 360/2

X = 180

HCF of two numbers = X = 180

And,

LCM of two numbers = X+900 = 900+180 = 1080.


we know that,

One Number × Other Number = HCF × LCM


Product of two numbers = 180 × 1080

Product of two numbers = 194400

HOPE IT WILL HELP YOU.... :-)