if the sum of m term of an AP is am square+bm,find the common difference
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Soln :-
Let m be 1,
so, = a + b = sum of first term = a = first term
Then, let m = 2,
so, = 4a + 2b = sum of two terms
second term = a2 = 4a + 2b - a - b
= 3a + b
So, d = a2 - a
= 3a + b - a - b
= 2a
Common difference = 2a(Solved)
Let m be 1,
so, = a + b = sum of first term = a = first term
Then, let m = 2,
so, = 4a + 2b = sum of two terms
second term = a2 = 4a + 2b - a - b
= 3a + b
So, d = a2 - a
= 3a + b - a - b
= 2a
Common difference = 2a(Solved)
aishurs23:
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