Question

If the sum of m terms of an A.P. is 3m2 + 4m, find the pth term.​

Answer 1

HELLO DEAR,

GIVEN:- Sm = 3m² + 4m,

S1 = 3 + 4 = a1 = 8

S2 = 12 + 8 = 20

and, S2 = a1 + a2

=> 20 = 7 + a2

=> a2 = 13

common diffrence d = a2 - a1 = 13 - 7 = 6

first term a = 7

an = a + (n - 1)d

now, put n = p

=> ap = 7 + (n - 1)6

=> ap = 6n + 1

hence, pth term is 6n + 1.

I HOPE IT'S HELP YOU DEAR,

THANKS

Answer 2

I hope it is helpful for you