If the sum of n consecutive odd numbers starting from 21 is equal to 125, then the value of n is
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Answer:
The correct answer will be 9.
Step-by-step explanation:
Let one number be x.
Then, the other number will be x+2.
The third number = x+2+2=x+4
It is given that their sum is 21.
So, x+(x+2)+(x+4)=21
3x+6=21
3x=15
x=5
and x+2=7
x+4=9.
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