If the sum of n term of an A.P is 3n2+5n find its 27th term
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Answer:
Sn=3n2+5n
s1 = 3+5=8
s2 = 12 +10=22
S3=27 +15=42
Ap=8,14, 20...:
a=8,d=6
a27=8+(27-I) 6
a27=8+26x6
a27=8+156=164. Ans.
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