if the sum of n term of an ap is 3n square-n and its common difference is 6 then its first term is
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Sn=3n²-n
S1=3(1)²-1
S1=3×1-1
S1=3-1
S1=2
Also S1 is equal to first term
So, The first term is 2
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S1=3(1)²-1
S1=3×1-1
S1=3-1
S1=2
Also S1 is equal to first term
So, The first term is 2
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
Vinayak333:
mark me BRAINLIEST
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