If the sum of n term of an ap is sn=3n2+5n then find its common difference
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Answered by
5
if n=1 then Sn=3×1+5
S1=8 and S2=11
apply sn general formula solve the eq you get d
Answered by
3
S_{1} = 3(1)^{2} + 5(1)
S_{1} = 3+5=8
Now S_{1} = a_{1} = 8
S_{2} = 3(2)^{2} + 5(2)
S_{2}= 12 + 10 = 22
S_{2} = a_{1} +a_{2}
a_{2} = S_{2} - a_{1}a_{2}= 22 - 8 = 14
d = a_{2} -a_{1}
d=14-8\\Therefore, d=6
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