if the sum of n term of the ap is 3x^2 +5x and its mth term is 164 then the value of m is
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Answer:
Let S
n
denote the sum of n terms and a
n
be the nth term of the given AP. Then,
S
n
=3n
2
+5n
S
n−1
=3(n−1)
2
+5(n−1)=3n
2
−n−2
Now, a
n
=S
n
−S
n−1
a
n
=(3n
2
+5n)−(3n
2
−n−2)
a
n
=6n+2
Now, a
m
=164
6m+2=164
6m=162
m=27
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