Question

If the sum of n terms in an A.P. is given by Sn = ( 3n2+ 2n) find it's nth term

Answer 1

Answer: nth term is 8n-1

Step-by-step explanation:

Here we are given $S_{n} = (3n^2+2n)$

Now,

by formula, $a_n = S_n -S_{n-1}$

$a_n=3n^2+2n-[3(n-1)^2+2(n-1)]$

$= 3n^2+2n-[3(n^2+1-2n]\\= 3n^2+2n-[3n^2+3-6n]\\= 3n^2+2n-3n^2-3+6n\\= 8n-3$

Hence, n^th term is 8n-3.

Answer 2

an= 6n-1

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