If the sum of n terms of an
a.P is 2 + 5, then find the 4th term.
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Answer:
Step-by-step explanation:
a3=a+2d
15=a+2d (1)
S10=10/2[2a+9d]
125=5[2a+9d]
25=2a+9d. (2)
Multiply (1) by 2
2a+4d=30
2a+9d=25
- - -
_________
-5d=5. =>d = -1
=>a = 17
Now,
a10 = a+9d
= 17+(-9)
= 17-9. =>8
Sn= n/2[2a+(n-1)d]
= n/2[34-n+1]
=n/2[35+n]
= 35n+n^2/2
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