If the sum of n terms of an A.P is 2n2 (square) - 3n , then what is the common difference .
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your common difference to Question is 4
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Choudharyshubham:
please mark as a brainliest
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s = 2n^2 - 3n
n/2(2a + (n-1)d ) = n(2n -3)
2a + (n-1)d = 2(2n-3)
d={2(2n-3)-2a}/(n-1)
n/2(2a + (n-1)d ) = n(2n -3)
2a + (n-1)d = 2(2n-3)
d={2(2n-3)-2a}/(n-1)
i think what shubham did is right u can delete my answer
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