Question

If the sum of n terms of an A.P. is (3n²-n) and its common difference is 6. then find 1st term
(a) 3 (b) 2
(c) 4 (d) 1​

Answer 1

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Answer 2

Answer:

The first term, a1 = 2

(b). 2

Step-by-step explanation:

Given,

The sum of n terms of an A.P. = 3n² - n

Common difference, d = 6

S1 = (3n² - n)

d = 6

Taking the value of n as a 1.

Now, putting 1 in place of n. By replacing n, we use 1 for finding the value of the first term.

Now, putting the given values.

=> a1 = (3 × 1² - 1)

=> a1 = 3 - 1

=> a1 = 2

.°. First term, a1 = 2