Question

If the sum of n terms of an A.P. is 4n-n2, then what is the sum of first two terms? Find the second term and the nth term.

Answer 1

Answer:

ₕₑyₐ ₘₐₜₑ☺❗ ₘᵣₖ ₘy ₐₙₛwₑᵣ ₐₛ bᵣₐᵢₙₗᵢₑₛₜ ₐₙd ₜₕₐₙₖₛ ₘₑ ₚₗₛₛₛ❗

Step-by-step explanation:

Wₑ ₕₐᵥₑ bₑₑₙ gᵢᵥₑₙ ,

ₛₙ ₌ ₄ₙ ₋ₙ^₂

ⱼᵤₛₜ ₜₕᵢₙₖ ₜₕₑ Gᵢᵥₑₙ ₑqᵤₐₜᵢₒₙ ₒf ₜₕₑ ₛᵤₘ ₒf " ₙ " ₜₑᵣₘₛ ᵢₛ cₒᵣᵣₑcₜ fₒᵣ ₐₗₗ ₜₕₑ ₜₑᵣₘₛ ᵢₙ ₜₕₑ ₐₚ , ₛₒ ᵢf yₒᵤ ₚᵤₜ ₙ₌₁ Yₒᵤ gₑₜ ₛᵤₘ ₒf ₁ ₜₑᵣₘₛ wₕᵢcₕ ᵢₛ ₐcₜᵤₐₗₗy ₜₕₑ ᵥₐₗᵤₑ ₒf fᵢᵣₛₜ ₜₑᵣₘ ₐ₁ .

ᵢₜ gₒₑₛ ₗᵢₖₑ ₜₕᵢₛ ,

ₛₙ ₌ ₄ₙ ₋ ₙ^₂

₌ ₄₍₁₎ ₋ ₍₁₎^₂

₌ ₄ ₋ ₁ ₌ ₃

ₛₒ ₜₕₑ Fᵢᵣₛₜ ₜₑᵣₘ ᵢₛ ₃.

ₛᵤₘ ₒf ₂ ₜₑᵣₘₛ ᵢₛ ...

ₛ₂ ₌ ₄₍₂₎ ₋ ₍₂₎^₂ ₌ ₄

ₛᵤₘ ₒf fᵢᵣₛₜ ₂ ₜₑᵣₘₛ ₘₑₐₙₛ ₐ₁ ₊ ₐ₂ ,

ₙₒw yₒᵤ ₖₙₒw ₐ₁ ₐₙd ₛ₂ , ₛₒ ₛ₂ ₋ ₐ₁ ₌ ₐ₂ ₌ ₄₋₃₌ ₁

ₙₒw ₜₕₑ cₒₘₘₒₙ dᵢffₑᵣₑₙcₑ ,

ₐ₂₋ ₐ₁ ₌ d ₌ ₁₋₃ ₌ ₋₂.

ₕₑₙcₑ ₜₕₑ Bₐₛᵢc ₘₑₜₕₒd ₒf Dₒᵢₙg ₜₕₐₜ wₐₛ ₜₕᵢₛ .

ₛₒₗᵥᵢₙg fₒᵣ ₐ₁₀ , ₐₙ , ₐ₃ wₑ gₑₜ ,

ₐ₃ ₌ ₋₁ ;

ₐ₁₀ ₌ ₋₁₅;

ₐₙ ₌ ₅ ₋ ₂ₙ ;

ₜₕₐₜ'ₛ ᵢₜ !

THANKS☺❗