Question

If the sum of n terms of an



a.P. Is np + 1 2 n (n – 1) q, where p and q are constants, then the common difference.

Answer 1

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Answer 2

Answer:

d = a2 - a1 = (P+Q)-P = Q. !!

Step-by-step explanation:

Let a1, a2,......an be the given A.P. Then

Sa = a1+a2+a3+...+a(n-1)+an

= nP + 1/2n(n-1)Q

Therefore,

S1 = a1 = P, S2 = a1 + a2 = 2P+Q

So that a2 = S2 - S1 = P+Q.

Hence, the Common difference is given by

d = a2 - a1 = (P+Q)-P = Q