If the sum of n terms of an A.P. is (pn+qn^2), where p and q are constants, find the common difference...
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➡️Given ,
Sn=pn +qn^2
we know ,Tn =Sn-S (n-1)
where Tn is nth term of AP
so,
Tn =pn+qn^2-q (n-1)^2-p (n-1)=q (n^2-n^2+2n-1)+p (n-n+1)=q (2n-1)+p
hence ,
Tn =q (2n-1)+p
put n=1
T1 = q+pn=2
T2 =3q +p
common difference =T2-T1=3q+p-q-p=2q
hence ,common difference =2q
》hope it helps u deaR..《
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